multithreading - New thread for each object in C# -

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• random number generator generating 1 random number 8 answers

i have following code:

thread[] threadarray= new thread[3]; myobject[] objectarray = new myobject[3];     (int = 0; < 3; i++)     {       //create new hotelsupplier object       objectarray[i] = new myobject();       //create array of threads , start new thread each hotelsupplier       threadarray[i] = new thread(new threadstart(objectarray[i].run));       //store name of thread       threadarray[i].name = i.tostring();       //start thread       threadarray[i].start();     } 

i creating 3 objects , 3 threads. of objects stored in array, of threads stored in array.

the run method in myobject generates random number between min , max

random random = new random(); double min = 50.00; double max = 500.00; double price =  random.nextdouble() * (max - min) + min; console.writeline("generating price: " + price); 

my output:

generating price: 101.271334780041 generating price: 101.271334780041 generating price: 101.271334780041 

i expect 3 different random numbers instead of 1 since each thread thought running on different object.

what doing wrong , not understand threads?

your original code causing random instances seeded same value.

the lowest impact way fix move code create random:

void run() {     //...     random random = new random();     //... } 

outside of run method , private static variable, becomes:

private static random random = new random(); void run() {     //... } 

so seeded once across instances of myobject.