asp.net mvc - Enabling MVCBuildViews based on Conditional Compilation Symbols -

is possible add conditional steps build check custom conditional compilation symbol , enable mvcbuildviews. i've found way based on build configuration

<propertygroup condition=" '$(configuration)|$(platform)' == 'release|anycpu' ">     <mvcbuildviews>true</mvcbuildviews> </propertygroup> 

but not sure how access compilation symbols instead.

the plan add symbol under project settings > build > conditional compilation symbols controls mvcbuildviews

assuming using c# need configure compiler use eg.test symbol when building views , need override configuration in web.config using following:

<system.codedom>       <compilers>         <compiler           language="c#;cs;csharp"           extension=".cs"           type="microsoft.csharp.csharpcodeprovider, system, version=2.0.3600.0, culture=neutral, publickeytoken=b77a5c561934e089"           compileroptions="/define:test" //here need define symbol           warninglevel="1" />       </compilers>     </system.codedom> 

if apply directly in web.config work define eg. test every time. should use web.config transformations symbol applied correct build configurations.

you can update projects created previous releases of mvc include build-time validation of views performing following steps:

1)open project file in text editor.

2)add following element under top-most element: <mvcbuildviews>true</mvcbuildviews>

3)at end of project file, uncomment <target name="afterbuild"> element , modify match following:

<target name="afterbuild" condition="'$(mvcbuildviews)'=='true'">     <aspnetcompiler virtualpath="temp" physicalpath="$(projectdir)\..\$(projectname)" /> </target>