c++ - How to copy a string into a char array with strcpy -

i trying copy value char.

my char array is

char sms_phone_number[15]; 

by way, tell me if should write (what benefic/difference?)

char * sms_phone_number[15] 

below displays string: "+417611142356"

splitedstring[1] 

and want give value sms_from_number

// strcpy(sms_from_number,splitedstring[1]);   // op's statement  strcpy(sms_phone_number,splitedstring[1]);  // edit  

i've got error, think because splitedstring[1] string, isn't?

sim908_cooking:835: error: invalid conversion 'char' 'char*'

so how can copy correctely. tried sprintf without success.

many thank help. cheers

i declare spliedstring this

// slitstring #define nbvals 9 char *splitedstring[nbvals]; 

i have function splitstring("toto,+345,titi",slitedstring)

void splitstring(char *ligne, char **splitedstring) {    char *p = ligne;    int = 0;   splitedstring[i++] = p;   while (*p) {       if (*p==',') {       *p++ = '\0';       if (i<nbvals){          splitedstring[i++] = p;       }     }      else     {       p++;     }    }   while(i<nbvals){     splitedstring[i++] = p;    } } 

if splitedstring display, display this

for(int i=0;i<4;i++){ serialprint(i);serial.print(":");serial.println(splitedstring[i]); }  //0:toto //1:+4176112233 //2:14/09/19 

i declared , want copy..

char sms_who[15]; char sms_phone_number[15]; char sms_data[15]; //and want copy  strcpy(sms_who,splitedstring[0] strcpy(sms_phone_number,splitedstring[1] strcpy(sms_date,splitedstring[2] 

i know, confused char , pointer * :o(