How to return specific option type by splitting a string using scala? -

i have following string , want split using scala

"myinfo": "name-name;model-model;number-10"

i want split value of myinfo string such can access myname , value seperately. e.g. myname:name, model:r210 etc

i using following code split string.

val data = (mainstring \ "myinfo").as[string].split("\\;").map(_.split("\\-").tolist)   .collect { case key :: value :: _ => key -> value }.tomap

it gives me desired result.

i using

data.get("name"),data.get("model"),data.get("number")

to access list. gives me results in string type. while want result of data.get("number") in integer format.

how result of 'number' in integer format?

data.get("number").map(_.toint)

will return option[int]

UIO